performance task #2
projectile motion lab
Procedure:
First we determined the final velocity of the ball, right before it left the wooden structure. This would also give us the initial velocity of the projectile.
To find the final velocity, a motion tracker device was used. The device determines how long it takes for an object to move between 2 points. We did four trials, and took the average time.
We then used the average time to get final velocity.
Since the reference angle is 0 degrees, the value is only used for the x component velocity.
We then compiled a list of known variables. We used the known y-component variables to find time. Time was then used to find the horizontal displacement.
First we determined the final velocity of the ball, right before it left the wooden structure. This would also give us the initial velocity of the projectile.
To find the final velocity, a motion tracker device was used. The device determines how long it takes for an object to move between 2 points. We did four trials, and took the average time.
We then used the average time to get final velocity.
Since the reference angle is 0 degrees, the value is only used for the x component velocity.
We then compiled a list of known variables. We used the known y-component variables to find time. Time was then used to find the horizontal displacement.
![Picture](/uploads/2/6/7/6/26767820/777569.png)
Calculating Vf
A motion tracker device was used to find the final velocity. What the device does is it measure the time it takes for an object to move between 2 points.
We did four different trials and took the average time.
Δ d = 1.55 cm = 0.0155m
Δ t1 = 0.007668 s
Δ t2= 0.007960 s
Δ t3= 0.007994 s
Δ t4= 0.007710 s
____________________
Δ tavg= 0.007833 s
Vf =( Δ d)/(Δ tavg)
= (0.0155m)/(0.007833 s)
= 1.978807609 m/s
A motion tracker device was used to find the final velocity. What the device does is it measure the time it takes for an object to move between 2 points.
We did four different trials and took the average time.
Δ d = 1.55 cm = 0.0155m
Δ t1 = 0.007668 s
Δ t2= 0.007960 s
Δ t3= 0.007994 s
Δ t4= 0.007710 s
____________________
Δ tavg= 0.007833 s
Vf =( Δ d)/(Δ tavg)
= (0.0155m)/(0.007833 s)
= 1.978807609 m/s
Calculating Δdx
![Picture](/uploads/2/6/7/6/26767820/8781192.png)
The horizontal displacement was calculated, using the kinematic equations. Up and to the right was established as positive.
As seen below, we used the known variables to find the the horizontal displacement.
As seen below, we used the known variables to find the the horizontal displacement.
Given
|
Solving for Δt
(Y - component) Δdy=ViyΔt - (ay(Δt^2))/2 2Δdy/ay = Δt^2 2(-0.924 m)/(-9.8m/s/s) = Δt^2 0.434248118 s = Δt Solving for Δdx (X-component) Δdx = VxΔt Δdx = (0.0434248118 s)(1.978807609 m/s) Δdx = 0.85929348 m |
Tracker Analysis
horizontal displacement vs time graph
vertical displacement vs time graph
velocity vs time graph
According to the tracker analysis, the horizontal displacement was (84.583m + 0.327m) 84.91 cm. Our calculations gave us a value of 85.9 cm.
The initial velocity of the ball was 212.962 cm/s, while our calculations gave us 197.88 cm/s.
The time it took was approximately 0.402 s, while our calculations estimated 0.434 s.
The initial velocity of the ball was 212.962 cm/s, while our calculations gave us 197.88 cm/s.
The time it took was approximately 0.402 s, while our calculations estimated 0.434 s.
Conclusion
Our calculations estimated the horizontal displacement was 0.85929348 m. According to tracker, the horizontal displacement was 0.84583 m. The calculations were off due to a combination of factors. First, air resistance was not considered a factor. Also, the height slightly changed every time the ball was dropped. And the horizontal distance may not have been measured properly.
The video was also shaky, and therefore not precise.
Our calculations estimated the horizontal displacement was 0.85929348 m. According to tracker, the horizontal displacement was 0.84583 m. The calculations were off due to a combination of factors. First, air resistance was not considered a factor. Also, the height slightly changed every time the ball was dropped. And the horizontal distance may not have been measured properly.
The video was also shaky, and therefore not precise.